x^2-10x+42=0

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Solution for x^2-10x+42=0 equation:


Simplifying
x2 + -10x + 42 = 0

Reorder the terms:
42 + -10x + x2 = 0

Solving
42 + -10x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-42' to each side of the equation.
42 + -10x + -42 + x2 = 0 + -42

Reorder the terms:
42 + -42 + -10x + x2 = 0 + -42

Combine like terms: 42 + -42 = 0
0 + -10x + x2 = 0 + -42
-10x + x2 = 0 + -42

Combine like terms: 0 + -42 = -42
-10x + x2 = -42

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = -42 + 25

Reorder the terms:
25 + -10x + x2 = -42 + 25

Combine like terms: -42 + 25 = -17
25 + -10x + x2 = -17

Factor a perfect square on the left side:
(x + -5)(x + -5) = -17

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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